\(\frac{3\left(2x-1\right)}{4}\) -\(\frac{3x+10}{10}\)+1=\(\frac{2\left(3x+2\right)}{5}\)
⇒\(\frac{15\left(2x-1\right)}{20}\)-\(\frac{6x+20}{20}\)+\(\frac{20}{20}\)=\(\frac{8\left(3x+2\right)}{20}\)
⇒15(2x-1)-6x-20+20-8(3x+2)=0
⇒30x-15-6x-24x-16=0
⇒0x-31=0(vô lý)
\(\frac{3\left(2x-1\right)}{4}-\frac{3x+1}{10}+1=\frac{2\left(3x+2\right)}{5}\)
\(\Leftrightarrow\) \(\frac{15\left(2x-1\right)}{20}-\frac{2\left(3x+1\right)}{20}+\frac{20}{20}=\frac{8\left(3x+2\right)}{20}\)
\(\Leftrightarrow\) 15(2x - 1) - 2(3x + 1) + 20 = 8(3x + 2)
\(\Leftrightarrow\) 30x - 15 - 6x - 2 + 20 = 24x + 16
\(\Leftrightarrow\) 24x + 3 = 24x + 16
\(\Leftrightarrow\) 24x - 24x = 16 - 3
\(\Leftrightarrow\) 0x = 13
Vì 0x luôn bằng 0 với mọi x nên 0x \(\ne\) 13
\(\Rightarrow\) Phương trình vô nghiệm.
Chúc bạn học tốt!
