\(\frac{2^3.6^4-4^4.3^5}{2^{10}.3^4}=\frac{2^3.\left(2.3\right)^4-\left(2^2\right)^4.3^5}{2^{10}.3^4}=\frac{2^3.2^4.3^4-2^8.3^5}{2^{10}.3^4}=\frac{2^7.3^4-2^8.3^5}{2^{10}.3^4}=\frac{2^7.3^4.\left(1-2.3\right)}{2^{10}.3^4}\)
\(=\frac{1-8}{2.3}=\frac{-7}{8}\)