Question

Tính:

a) \(\frac{\left[\left(-2\right)^2\right]^5}{\left(-2\right)^3\left(-2\right)^2\left(-4\right)^2}\)b) \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6}\)

Answer 1

a) \(=\frac{\left(-2\right)^{10}}{\left(-2\right)^7}=\frac{\left(-2\right)^7.\left(-2\right)^3}{\left(-2\right)^7}=\left(-2\right)^3=-8\)

b) \(=\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2.3}=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2.3}=\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{12}.3^{10}.\left(3^2-2^{-11}.3^{-9}\right)}=\frac{6}{3^2-2^{-11}.3^{-9}}\)

\(=\frac{2.3}{3.\left(3-2^{-11}.3^{-10}\right)}=\frac{2}{3-2^{-11}.3^{-10}}\)