f) \(\frac{x^2-x}{x+1}\)
tìm x biết
a)
\(\frac{1}{2}\)+\(\frac{2}{3}\).x=\(\frac{4}{5}\)
b)
x+\(\frac{1}{4}\)=\(\frac{4}{3}\)|
c)
\(\frac{3}{5}x-\frac{1}{2}=-\frac{1}{7}\)
|d)
\(\left|x+5\right|-6=9\)
e)
\(\left|x-\frac{4}{5}\right|=\frac{3}{4}\)
f)
\(\frac{1}{2}-\left|x\right|=\frac{1}{3}\)
g)
\(^{x^2}\)=16
h)
\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
i)
\(^{3^3}\).x=\(^{3^6}\)
j)
\(\frac{1,35}{0,2}=\frac{1,25}{x}\)
k)
\(1\frac{2}{3}:x=6:0,3\)
a,\(\frac{-5}{6}\) - x = \(\frac{7}{12}\) + \(\frac{-1}{3}\)
b,\(\frac{x+3}{-15}\) = \(\frac{1}{3}\)
c, \(\frac{-15}{x-1}\)=\(\frac{-3}{5}\)
d,\(\frac{1}{2}\)x-\(\frac{2}{5}\)=\(\frac{1}{5}\)
e,-\(\frac{2}{3}\)x+\(\frac{1}{5}\)=\(\frac{1}{10}\)
f,\(\frac{4}{5}\)- \(\frac{1}{2}\)x = \(\frac{1}{10}\)
a) \(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16\frac{2}{3}\right)=0\)
b) \(\left(\frac{x}{3}-5\frac{1}{4}\right)^2-\frac{-2}{5}=1\frac{1}{25}\)
c) \(\frac{17-x}{12}=\frac{3}{17-x}\)
d) \(1\frac{1}{3}-25\%\left(x-\frac{8}{3}\right)+2x=1,6:\frac{3}{5}\)
tìm x biết \(\frac{2}{3}x:\frac{1}{5}=1\frac{1}{5}:25\%\)
Tìm x\(\varepsilon\)biết \(\frac{4}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\)<x<\(\frac{2}{3}\).\(\left(\frac{-1}{6}+\frac{3}{4}\right)\)
|2x-3|-x=21
|\(\frac{1}{2}\)x-\(\frac{1}{3}\)|-|\(\frac{1}{3}\)x+\(\frac{1}{2}\)|=0
tìm x
a) \(\frac{x-8}{2x-17}\)
b) \(\frac{x-4}{x+1}\)
c) \(\frac{10}{x+7}\)
d)\(\frac{x-1}{x^2}\)
1.1 Tính D =\(\frac{1}{1.2}\)+\(\frac{1}{2.3}\)+\(\frac{1}{3.4}\)+\(\frac{1}{4.5}\)+...+\(\frac{1}{2018.2019}\)
1.2 Tìm x, biết: \(\frac{1}{2}\).x - 0,25.x + 3\(\frac{1}{4}\).x = \(\frac{-3}{2}\)+ 12,5%
Tìm x biết
\(\left(2.x-1\right).\left(-\frac{3}{4}.x+\frac{1}{2}\right)=0\)