Question

Tìm x biết

\(\left(2.x-1\right).\left(-\frac{3}{4}.x+\frac{1}{2}\right)=0\)

Answer 1

\(\left(2.x-1\right)\left(-\frac{3}{4}x+\frac{1}{2}\right)=0\)

=>\(\left[{}\begin{matrix}2.x-1=0\\-\frac{3}{4}x+\frac{1}{2}=0\end{matrix}\right.\)=>\(\left[{}\begin{matrix}x=\frac{1}{2}\\x=\frac{2}{3}\end{matrix}\right.\)

Answer 2

\(\left(2x-1\right).\left(-\frac{3}{4}.x+\frac{1}{2}\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2.x-1=0\\-\frac{3}{4}.x+\frac{1}{2}=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}2.x=1\\-\frac{3}{4}.x=-\frac{1}{2}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\frac{1}{2}\\x=\frac{2}{3}\end{matrix}\right.\)