2KClO3--->2KCl+O2
n KClO3=24,5/122,5=0,2(mol)
Theo pthh
n O2=1/2n KMnO3=0,1(mol)
V O2=0,1.22,4=2,24(l)
\(n_{KClO_{3}}=\dfrac{m_{KClO_{3}}}{M_{KClO_{3}}}=\dfrac{24,5}{122,5}=0,2(mol)\)
\(2KClO_{3}\) ➝ \(2KCl+3O_{2}\)
Theo PTHH: \(n_{O_{2}}=\dfrac{3}{2}n_{KClO_{3}}=\dfrac{3}{2}.0,2=0,3(mol)\)
\(V_{O_{2}}=n_{O_{2}}.22,4=0,3.22,4=6,72(l)\)