Ta có: \(\left\{{}\begin{matrix}m_{H_2O}=0,9\left(g\right)\\m_{CO_2}=2,2\left(g\right)\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}n_{H_2O}=0,05\left(mol\right)\\n_{CO_2}=0,05\left(mol\right)\end{matrix}\right.\)
\(m_{O_2}=\dfrac{1,12}{22,4}.32=1,6\left(g\right)\)
\(\Rightarrow m_{C_xH_yO_z}=0,9+2,2-1,6=1,5\left(g\right)\)
\(\Rightarrow M_{C_xH_yO_z}=60\left(\dfrac{g}{mol}\right)\)
\(n_H=0,1\left(mol\right)\Rightarrow m_H=0,1\left(g\right)\)
\(n_C=0,05\left(mol\right)\Rightarrow m_C=0,6\left(g\right)\)
\(\Rightarrow m_O=1,5-0,1-0,6=0,8\left(g\right)\Rightarrow n_O=0,05\left(mol\right)\)
\(x:y:z=0,05:0,1:0,05=1:2:1\)
\(\Rightarrow\left[CH_2O\right]_n=60\)
\(\Rightarrow n=2\\ \Rightarrow CTPT:C_2H_4O_2\)
