Ta có:
\(\left\{{}\begin{matrix}n_{CO2}=\frac{13,44}{22,4}=0,6\left(mol\right)\\n_{H2O}=\frac{16,2}{18}=0,9\left(mol\right)\end{matrix}\right.\)
Bảo toàn C, H :
\(\Rightarrow m_C+m_H=0,6.12+0,9.2=9\left(g\right)\)
Nên A gồm C,H
\(\Leftrightarrow\frac{n_C}{n_H}=\frac{0,6}{0,9.2}=\frac{1}{3}\)
CTĐGN : (CH3)n
\(\Rightarrow15n< 30\Rightarrow n\le2\)
Biện luận :
\(n=2\Rightarrow C_2H_6\left(TM\right)\)
Vậy CTPT là C2H6