Ta có:
\(\dfrac{x}{2}=\dfrac{y}{3}=k\)
Theo đề bài, ta có :
\(xy=54\Rightarrow2k.3k=54\)
\(\Rightarrow5k=54\Rightarrow k=10,8\)
Ta thấy :
\(\dfrac{x}{2}=10,8\Rightarrow x=10,8.2=21,6\)
\(\dfrac{y}{3}=10,8\Rightarrow y=10,8.3=32,4\)
Đặt :\(\dfrac{x}{2}=\dfrac{y}{3}=k\Leftrightarrow\left\{{}\begin{matrix}x=2k\\y=3k\end{matrix}\right.\)
mà \(xy=54\)
hay 2k . 3k = 54
\(\Rightarrow6.k^2=54\)
\(\Rightarrow k^2=9=\left(\pm3\right)^2\)
Với k = 3 \(\Rightarrow\) \(x=2.3=6;y=3.3=9\)
Với k = -3 \(\Rightarrow x=2.\left(-3\right)=-6;y=3.\left(-3\right)=-9\)