Câu hỏi của ABC

Question

$\dfrac{x+1}{2015}+\dfrac{x+2}{2014}+\dfrac{x+3}{2013}=-3$

Mashiro Shiina · Accepted Answer

$\dfrac{x+1}{2015}+\dfrac{x+2}{2014}+\dfrac{x+3}{2013}=-3$

$\left(\dfrac{x+1}{2015}+1\right)+\left(\dfrac{x+2}{2014}+1\right)+\left(\dfrac{x+3}{2013}+1\right)=0$

$\dfrac{x+2016}{2015}+\dfrac{x+2016}{2014}+\dfrac{x+2016}{2013}=0$

$\left(x+2016\right)\left(\dfrac{1}{2015}+\dfrac{1}{2014}+\dfrac{1}{2013}\right)=0$

$\Rightarrow x+2016=0\Rightarrow x=-2016$Câu trả lời: $\dfrac{x+1}{2015}+\dfrac{x+2}{2014}+\dfrac{x+3}{2013}=-3$

$\left(\dfrac{x+1}{2015}+1\right)+\left(\dfrac{x+2}{2014}+1\right)+\left(\dfrac{x+3}{2013}+1\right)=0$

$\dfrac{x+2016}{2015}+\dfrac{x+2016}{2014}+\dfrac{x+2016}{2013}=0$

$\left(x+2016\right)\left(\dfrac{1}{2015}+\dfrac{1}{2014}+\dfrac{1}{2013}\right)=0$

$\Rightarrow x+2016=0\Rightarrow x=-2016$

Đức Hiếu · Answer

$\dfrac{x+1}{2015}+\dfrac{x+2}{2014}+\dfrac{x+3}{2013}=-3$

$\Rightarrow\dfrac{x+1}{2015}+1+\dfrac{x+2}{2014}+1+\dfrac{x+3}{2013}+1=0$

$\Rightarrow\dfrac{x+2016}{2015}+\dfrac{x+2016}{2014}+\dfrac{x+2016}{2013}=0$

$\Rightarrow\left(x+2016\right).\left(\dfrac{1}{2015}+\dfrac{1}{2014}+\dfrac{1}{2013}\right)=0$

$\Rightarrow x+2016=0\Rightarrow x=-2016$

Chúc bạn học tốt!!!Câu trả lời: $\dfrac{x+1}{2015}+\dfrac{x+2}{2014}+\dfrac{x+3}{2013}=-3$

$\Rightarrow\dfrac{x+1}{2015}+1+\dfrac{x+2}{2014}+1+\dfrac{x+3}{2013}+1=0$

$\Rightarrow\dfrac{x+2016}{2015}+\dfrac{x+2016}{2014}+\dfrac{x+2016}{2013}=0$

$\Rightarrow\left(x+2016\right).\left(\dfrac{1}{2015}+\dfrac{1}{2014}+\dfrac{1}{2013}\right)=0$

$\Rightarrow x+2016=0\Rightarrow x=-2016$

Chúc bạn học tốt!!!

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