\(\Leftrightarrow2-2x=6-3x\\ \Leftrightarrow x=4\)
\(\Leftrightarrow2-2x=6-3x\\ \Leftrightarrow x=4\)
I : tìm x
a) (x-1)(x-5)>0
b) (x-1)(x-5)<0
c) \(\dfrac{3}{4}-\dfrac{1}{4}\left|x-\dfrac{1}{7}\right|=\dfrac{1}{4}\)
d) \(\left(x-\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)
e) 8 (x+1) -2(2x+5)=0
g) ( 6x-1)-(x+8)=0
h)\(\left|7x-\dfrac{1}{4}\right|=1\)
q) -2x-3=-x+7
các bạn giúp mình với xin đó đấy
Tìm x bik : a. \(0,5.\left(x-\dfrac{1}{3}\right)-\dfrac{1}{2}=x+\dfrac{-4}{5}\) b. \(\dfrac{2}{3}.\left(\dfrac{1}{2}.x-\dfrac{1}{3}\right)+\dfrac{1}{2}=\dfrac{2}{3}-x\)
Tìm x biết
1, \(\dfrac{-1}{4}-\dfrac{3}{4}:x=-\dfrac{11}{36}\)
2,\(\dfrac{3}{4}x-\dfrac{1}{2}=\dfrac{3}{7}\)
tìm x :
a) \(\dfrac{x+1}{7}+\dfrac{x+1}{8}=\dfrac{x+1}{9}+\dfrac{x+1}{10}\)
b) \(\dfrac{x+1}{12}+\dfrac{x^2}{11}=\dfrac{x+3}{10}+\dfrac{x+4}{9}\)
c) \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
d)\(\dfrac{3x+2}{5x+7}=\dfrac{3x-1}{5x-3}\)
2 tìm x,y,z
a) \(\dfrac{x}{2}=\dfrac{y}{3},\dfrac{y}{4}=\dfrac{z}{5}vàx^2-y^2=-16\)
b)2x=3y,5x=7z và 3x-7y+5z=30
Bài 1:
a)\(\left|x-2\right|\)+\(\left|1-\dfrac{x}{2}\right|\)=0 b)\(\left(x-\dfrac{1}{3}\right)^3\)=\(\dfrac{-8}{27}\)
c)\(\dfrac{x^2}{6}\)=\(\dfrac{24}{25}\) c)\(\dfrac{x-1}{x+5}\)=\(\dfrac{6}{7}\)
Giúp mik làm bài này với ạ mik đang cần gấp tối nay mik phải nộp rồi mong mn giúp đỡ mik. Mik cảm ơn mn
1 , Tính : \(\dfrac{2}{3}.\left\{{}\begin{matrix}2\\3\end{matrix}\right.-\dfrac{2}{3}.\left[\dfrac{2}{3}-\dfrac{2}{3}.\left(\dfrac{2}{3}-\dfrac{1}{2}\right)\right]\) 2 Tìm x bik : \(0,2.\left(x-\dfrac{1}{2}\right)-0,2=x-1\)
Tìm x,y,z bt
\(1.\dfrac{x}{3}=\dfrac{y}{6};4x-y=42\)
\(2.\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5};x-2y+3z=33\)
\(3.\dfrac{x}{y}=\dfrac{6}{5};x+y=121\)
Tìm \(x\)
a) \(2.\left|\dfrac{1}{2}x-\dfrac{1}{3}\right|=1\dfrac{2}{5}\)
b) \(\left|\dfrac{1}{4}x-2\dfrac{1}{5}\right|=\left|0,6-\dfrac{2}{3}x\right|\)
c) \(\left|2x-\dfrac{1}{3}\right|=x+\dfrac{1}{2}\)
b) -x - 2 = \(\dfrac{5}{4}\) c) \(\dfrac{4}{3}-\left(x-\dfrac{1}{5}\right)=\left|\dfrac{-3}{10}+\dfrac{1}{2}\right|-\dfrac{1}{6}\) d) \(\dfrac{1}{3}-\left(\dfrac{2}{3}-x+\dfrac{5}{4}\right)=\dfrac{7}{12}-\left(\dfrac{5}{2}-\dfrac{13}{6}\right)\)