Question

\(\dfrac{\left(\dfrac{2}{3}\right)^3\cdot\left(\dfrac{-3}{4}\right)^2\cdot\left(-1\right)^{2019}}{\left(\dfrac{2}{5}\right)^2\cdot\left(\dfrac{-5}{12}\right)^3}\)

Tính hộ mk với

Answer 1

\(=\dfrac{\dfrac{2^3\cdot3^2}{3^3\cdot4^2}\cdot\left(-1\right)}{\dfrac{2^2\cdot\left(-5\right)^3}{5^2\cdot2^6\cdot3^3}}=\dfrac{-\dfrac{1}{2}\cdot\dfrac{1}{3}}{-\dfrac{1}{2^4}\cdot5\cdot\dfrac{1}{3^3}}=\dfrac{1}{6}:\dfrac{5}{2^4\cdot3^3}\)

\(=\dfrac{1}{6}\cdot\dfrac{2^4\cdot3^3}{5}=\dfrac{2^3\cdot3^2}{5}=\dfrac{72}{5}\)