Lời giải:
ĐKXĐ: $x\neq \pm 4$
PT $\Leftrightarrow \frac{8(x-4)+8(x+4)}{x^2-16}=\frac{25}{3}$
$\Leftrightarrow \frac{16x}{x^2-16}=\frac{25}{3}$
$\Rightarrow 48x=25x^2-400$
$\Leftrightarrow 25x^2-48x-400=0$
$\Leftrightarrow (5x-\frac{24}{5})^2=\frac{10576}{25}$
$\Rightarrow x=\frac{24\pm 4\sqrt{661}}{25}$ (đều thỏa mãn)
\(\dfrac{1}{x^2 +x}\)+\(\dfrac{1}{x^2+3x+2}\)+\(\dfrac{1}{x^2+5x+6}\)=\(\dfrac{x}{x(x+3)}\)
giải hộ mình pt này với ạ
giải pt:
\(\dfrac{x+1}{9}+\dfrac{x+2}{8}=\dfrac{x+3}{7}+\dfrac{x+4}{6}\)
BÀI 1: Giải phương trình sau:
a. (x - 4)3 = (x + 4)(x2 - x - 16)
b. \(\dfrac{x+2}{x}=\dfrac{x^2+5x+4}{x^2+2x}+\dfrac{x}{x+2}\)
c. \(\dfrac{x+1}{x-2}-\dfrac{5}{x+2}=\dfrac{12}{x^2-4}+1\)
d. (x + 3)2 - 25 = 0
e. \(\dfrac{3}{2x+10}+\dfrac{2x}{25-x^2}+\dfrac{3}{x-5}=0\)
f. \(\dfrac{x+5}{x-1}-\dfrac{x-1}{x-3}=\dfrac{8}{x^2-4x-3}\)
BÀI 2: Tìm m để phương trình sau số nghiệm x = 1:
3.(2x + m)(x + 2) - 2.(2x+1) = 18
BÀI 3: Giải phương trình:
a. (x-2)2 - 4.(x + 3) = x.(x-4)
b. \(\dfrac{3}{x+1}+\dfrac{x-1}{x-2}=\dfrac{x}{x-2}\)
c. \(\dfrac{x}{2x-6}+\dfrac{x}{2x+2}=\dfrac{2x^2}{x^2-2x-3}\)
d. (x + 3)2 - (x - 3)2 = 6x + 18
e. \(\dfrac{x+3}{x-2}=\dfrac{5}{\left(x-2\right)\left(3-x\right)}\)
f. \(\dfrac{12x^2+30x-21}{16x^2-9}-\dfrac{3x-7}{3-4x}=\dfrac{6x+5}{4x+3}\)
g. \(\dfrac{4}{x+1}-\dfrac{2}{x-2}=\dfrac{x+3}{x^2-x-2}\)
GIÚP MÌNH VỚI NHA !!!!
Giải phương trình :
\(\dfrac{x+1}{9}+\dfrac{x+2}{8}=\dfrac{x+3}{7}+\dfrac{x+4}{6}\)
k) 8 - \(\dfrac{x-2}{2}\) = \(\dfrac{x}{4}\)
m) \(\dfrac{3x+2}{2}\) - \(\dfrac{3x+1}{6}\) = 2x + \(\dfrac{5}{3}\)
n) \(\dfrac{x+1}{7}\)+ \(\dfrac{x+2}{6}\) = \(\dfrac{x+3}{5}\) + \(\dfrac{x+4}{4}\)
o) \(\dfrac{x+5}{6}\) + \(\dfrac{x+6}{5}\) = x + 9
Bài 1:
a) \(\dfrac{3-x}{12}=\dfrac{2x+2}{8}\)
b) \(\dfrac{x+3}{x-4}+\dfrac{x-3}{x+4}=\dfrac{2\left(x^2+12\right)}{x^2-16}\)
Bài 1: Giải các phương trình sau:
a. 7-( 2x + 4 ) = - (x+4)
b.\(\dfrac{2x}{x+1}=\dfrac{x^2-x+8}{\left(x+1\right)\left(x-4\right)}\)
c.\(\dfrac{2\left(3x+5\right)}{3}-\dfrac{x}{2}=5-\dfrac{3\left(x+1\right)}{4}\)
Giải các pt sau:
a) \(\dfrac{x}{x+2}=\dfrac{x^2+4}{x^2-4}\)
b) \(\dfrac{x}{2x-6}+\dfrac{x}{2x+2}+\dfrac{2x}{\left(x+1\right)\left(3-x\right)}=0\)
c) \(\dfrac{2-x}{2017}-1=\dfrac{1-x}{2018}-\dfrac{x}{2019}\)
Giải các phương trình :
a) \(\dfrac{1}{2x-3}-\dfrac{3}{x\left(2x-3\right)}=\dfrac{5}{x}\)
b) \(\dfrac{x+2}{x-2}-\dfrac{1}{x}=\dfrac{2}{x\left(x-2\right)}\)
c) \(\dfrac{x+1}{x-2}+\dfrac{x-1}{x+2}=\dfrac{2\left(x^2+2\right)}{x^2-4}\)
d) \(\left(2x+3\right)\left(\dfrac{3x+8}{2-7x}+1\right)=\left(x-5\right)\left(\dfrac{3x+8}{2-7x}+1\right)\)
