\(\Leftrightarrow\dfrac{7^x.7^2+7^x.7+7^x}{57}=\dfrac{5^{2x}+5^{2x}.5+5^{2x}.5^3}{131}\)
\(\Leftrightarrow7^x\left(\dfrac{7^2+7+1}{57}\right)=5^{2x}\left(\dfrac{1+5+5^3}{131}\right)\)
\(\Leftrightarrow7^x\dfrac{57}{57}=5^{2x}\dfrac{131}{131}\Leftrightarrow7^x=5^{2x}\Leftrightarrow7^x=25^x\Leftrightarrow x=0\)
Câu 10:Tìm biết
Trả lời
tìm x , biết :
a, \(\dfrac{37-x}{2x+5}=\dfrac{4}{9}\)
b, \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)
c, \(\dfrac{x+3}{25}=\dfrac{9}{x+3}\)
d, \(\dfrac{x}{\dfrac{-2}{3}}=\dfrac{5}{-x}\)
e, \(\dfrac{2x-5}{\dfrac{3}{2}}=\dfrac{\dfrac{-27}{8}}{5-2x}\)
f, \(\dfrac{\dfrac{5}{9}}{\left(3x-1\right)^2}=\dfrac{1-2x}{\dfrac{25}{3}}\)
1. tìm x
a.\(x+\dfrac{1}{2}=5^3:5^2\)
b. \(\dfrac{x-1}{-15}\)=\(\dfrac{-60}{x-1}\)
c. \(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
Tìm x :
a) \(\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
b) \(\dfrac{2}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
c) \(\dfrac{x+2014}{2}+\dfrac{2x+4028}{7}=\dfrac{x+2009}{5}+\dfrac{x+2020}{6}\)
d)\(\dfrac{3}{\left(x+2\right)\left(x+5\right)}+\dfrac{5}{\left(x+5\right)\left(x+10\right)}+\dfrac{7}{\left(x+10\right)\left(x+18\right)}=\dfrac{x}{\left(x+2\right)\left(x+17\right)}\)
Help me , bn nào giải đc bài nò thì giải nha !!! =))
Tìm x :
a) \(3^{x+1}+2x.3^x-18x-27=0\)
b) \(\dfrac{1}{2}\left|2x+5\right|-\dfrac{5}{4}\left|4x+10\right|+\dfrac{7}{3}\left|-20-8x\right|=\dfrac{1}{6}\)
Tìm x, biết rằng:
1) ( 2x + 1)3 = -0,001
2) ( 2x -3 )4 = ( 2x-3 )6
3) ( 2x+1 )5 = ( 2x+1)2010
4) \(\dfrac{8}{25}=\dfrac{2^x}{5^{x-1}}\)
5) 9x : 3x = 3
6) \(3^x+3^{x+3}=756\)
7) \(5^{x+1}+6.5^{x+1}=875\)
8) \(2^{x-1}.3^{y+1}=12^{x+9}\)
9) \(3^x=9^{y-1}\)
10) \(2^{x+1}.5^y=20^x\)
11) 15x : 3y = 75y
12) \(\dfrac{3}{5}:\dfrac{2x}{15}=\dfrac{1}{2}:\dfrac{4}{5}\)
13) \(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}\) và xy + yz + zx = 104
Tìm x ; y biết : \(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
Câu hỏi:
a) -4x(x-5)-2x(8-2x)=3
b) \(\dfrac{2x-1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
Giúp mik nhé! Cảm ơn bn nhiều!
Tìm x :
a) \(3-\dfrac{2}{2x-3}=\dfrac{2}{5}+\dfrac{1}{2x-3}-\dfrac{3}{2}\)
b) \(7.\left(x.1\right)+2x.\left(1-x\right)=0\)
c) \(\dfrac{x+1}{2018}+\dfrac{x+2}{2017}+\dfrac{x+3}{2016}=\dfrac{x+10}{2009}+\dfrac{x+11}{2008}+\dfrac{x+12}{2007}\)
Có 3 ý thui các bạn hãy giúp mk!!!!!!
