\(\dfrac{2x+1}{3}=\dfrac{x-5}{2}\\ \Leftrightarrow\dfrac{2\cdot\left(2x+1\right)}{6}=\dfrac{3\cdot\left(x-5\right)}{6}\\ \Leftrightarrow\dfrac{4x+2}{6}=\dfrac{3x-15}{6}\\ \Leftrightarrow4x+2=3x-15\\ \Leftrightarrow4x-3x=\left(-15\right)-2\\ \Leftrightarrow x=-17\)
Vì \(\dfrac{2x+1}{3}=\dfrac{x-5}{2}\)
\(\Rightarrow\left(2x+1\right).2=\left(x-5\right).3\)
\(\Rightarrow4x+2=3x-15\)
\(\Rightarrow4x-3x=\left(-15\right)-2\)
\(\Rightarrow x=-17\)
Vậy \(x=-17\)