Question

\(\dfrac{1}{3}\)- \(\dfrac{2}{5}\)+ 3x=\(\dfrac{3}{4}\)

Answer 1

\(\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}\)

\(3x=\dfrac{1}{3}-\dfrac{2}{5}-\dfrac{3}{4}\)

\(3x=-\dfrac{49}{60}\)

\(x=-\dfrac{49}{60}:3\)

\(x=-\dfrac{49}{180}\)

Answer 2

\(\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}\)

\(\Rightarrow\dfrac{2}{5}+3x=\dfrac{1}{3}-\dfrac{3}{4}\)

\(\Rightarrow\dfrac{2}{5}+3x=-\dfrac{5}{12}\)

\(\Rightarrow3x=-\dfrac{49}{60}\)

\(\Rightarrow x=-\dfrac{49}{180}\)

Answer 3

\(\dfrac{1}{3}-\dfrac{2}{5}+3x=\dfrac{3}{4}\)

\(\dfrac{3}{4}-3x=\dfrac{1}{3}-\dfrac{2}{5}\)

\(\dfrac{3}{4}-3x=-\dfrac{1}{15}\)

\(\dfrac{3}{4}+\dfrac{1}{15}=3x\)

\(\dfrac{49}{60}=3x\)

\(x=\dfrac{49}{180}\)

Vậy \(x=\dfrac{49}{180}\)