Question

\(\dfrac{-5}{6}\) + \(\dfrac{8}{3}\) + \(\dfrac{-29}{6}\) ≤ x ≤ \(\dfrac{-1}{2}\) + 2 + \(\dfrac{5}{2}\)

Answer 1

`[-5]/6+8/3+[-29]/6 <= x <= [-1]/2+2+5/2`

`[-5]/6+16/6+[-29]/6 <= [6x]/6 <= [-3]/6+12/6+15/6`

`-5+16-29 <= 6x <= -3+12+15`

`-18 <= 6x <= 24`

`-18:6 <= 6x:6 <= 24:6`

`-3 <= x <= 4`

Vậy `-3 <= x <= 4`

Answer 2

\(=>-3\le x\le4\)

\(=>x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)

Answer 3

`=>` Ta có STN:

`<=> -3 <= x <= 4`

`<=> x = {-3; -2; -1; 0; 1; 2; 3; 4}`

`<=> x in Z`