\(\dfrac{-4}{8}-\left(\dfrac{-1}{3}-x\right)=\dfrac{2}{5}\\ \dfrac{-1}{3}-x=\dfrac{-4}{8}-\dfrac{2}{5}\\\dfrac{-1}{3}-x=\dfrac{-9}{10}\\ x=\dfrac{-1}{3}+\dfrac{9}{10}\\ x=\dfrac{17}{30} \)
\(\dfrac{-4}{8}-\left(\dfrac{-1}{3}-x\right)=\dfrac{2}{5}\\ \left(\dfrac{-1}{3}-x\right)=\dfrac{-4}{8}-\dfrac{2}{5}\\\left(\dfrac{-1}{3}-x\right)=\dfrac{-9}{10}\\ x=\dfrac{-1}{3}-\dfrac{-9}{10}\\ x=\dfrac{17}{30}.\)