Violympic toán 6
Các câu hỏi tương tự
1. Tìm x, biết:
a, 1dfrac{3}{5} + dfrac{dfrac{2}{7}+dfrac{2}{17}+dfrac{2}{37}}{dfrac{5}{7}+dfrac{5}{17}+dfrac{5}{37}} . x dfrac{16}{5}
b, (dfrac{1}{24.25} + dfrac{1}{25.26} + . . . + dfrac{1}{39.40} ) . 120 + x. dfrac{1}{3} -4
c, left|x-dfrac{1}{3}right| . 2 + dfrac{4}{5} 0,24
d, dfrac{24}{7x-3} dfrac{-4}{25}
e, ( 50% x + 5dfrac{1}{4} ) , dfrac{-2}{3} 2dfrac{5}{6}
f, 1dfrac{1}{3} - 25%dfrac{-5}{12} + 2x 1,6 : dfrac{3}{5}
Đọc tiếp
1. Tìm x, biết:
a, \(1\dfrac{3}{5}\) + \(\dfrac{\dfrac{2}{7}+\dfrac{2}{17}+\dfrac{2}{37}}{\dfrac{5}{7}+\dfrac{5}{17}+\dfrac{5}{37}}\) . x = \(\dfrac{16}{5}\)
b, (\(\dfrac{1}{24.25}\) + \(\dfrac{1}{25.26}\) + . . . + \(\dfrac{1}{39.40}\) ) . 120 + x. \(\dfrac{1}{3}\) = -4
c, \(\left|x-\dfrac{1}{3}\right|\) . 2 + \(\dfrac{4}{5}\) = 0,24
d, \(\dfrac{24}{7x-3}\) = \(\dfrac{-4}{25}\)
e, ( 50% x + \(5\dfrac{1}{4}\) ) , \(\dfrac{-2}{3}\) = \(2\dfrac{5}{6}\)
f, \(1\dfrac{1}{3}\) - 25%\(\dfrac{-5}{12}\) + 2x = 1,6 : \(\dfrac{3}{5}\)
Tìm \(x\)
1. \(\dfrac{1}{7}=\dfrac{8}{-x}\)
2. \(\dfrac{3x}{9}=\dfrac{2}{6}\)
3. \(4\dfrac{2}{5}:\left(\dfrac{-33}{10}\right)+x=-1\dfrac{5}{6}\)
4. \(45\%.x-2\dfrac{3}{8}=-1\dfrac{31}{40}\)
5. \(\left(x-2\dfrac{1}{4}\right):\left(-\dfrac{5}{6}\right)=3\)
1: \(\dfrac{2\cdot\left(x+2\right)}{3}-\dfrac{5\cdot\left(x-1\right)}{4}=\dfrac{3\cdot\left(5-x\right)}{2}-1\dfrac{1}{2}\cdot\left(2x+3\right)\)
tìm x biết
a) dfrac{2}{3}: x - dfrac{5}{6} 1dfrac{1}{2}
b) (dfrac{5}{6} . x + dfrac{2}{3}) : (dfrac{2}{5} +1dfrac{1}{3} )dfrac{4}{9}
c) |x - dfrac{4}{3}| - dfrac{5}{6} dfrac{3}{5} . 1dfrac{1}{2}
d) |2x + dfrac{1}{2}| - dfrac{3}{4}3dfrac{1}{2}
e) |dfrac{3}{2}x - dfrac{5}{6}|+ dfrac{12}{5} 1dfrac{1}{2}
Đọc tiếp
tìm x biết
a) \(\dfrac{2}{3}\): x - \(\dfrac{5}{6}\)= 1\(\dfrac{1}{2}\)
b) (\(\dfrac{5}{6}\) . x + \(\dfrac{2}{3}\)) : (\(\dfrac{2}{5}\) +\(1\dfrac{1}{3}\) )\(\dfrac{4}{9}\)
c) \(|\)x - \(\dfrac{4}{3}\)\(|\) - \(\dfrac{5}{6}\) = \(\dfrac{3}{5}\) . \(1\dfrac{1}{2}\)
d) \(|\)2x + \(\dfrac{1}{2}\)\(|\) - \(\dfrac{3}{4}\)=\(3\dfrac{1}{2}\)
e) \(|\dfrac{3}{2}\)x - \(\dfrac{5}{6}|\)+ \(\dfrac{12}{5}\)= \(1\dfrac{1}{2}\)
\(\left(\dfrac{1}{3}-\dfrac{1}{2}\right)^{x-2}=\dfrac{1}{216}\)
\(\left[\left(\dfrac{1}{3}-\dfrac{1}{2}\right)^{x-5}\right]^{x-1}=\dfrac{1}{36}\)
tìm x biết :
1.\(\dfrac{-5}{6}+\dfrac{8}{3}+\dfrac{-29}{6}\le x\le\dfrac{-1}{2}+2+\dfrac{5}{2}\)
2.\(\left(2,7x-1\dfrac{1}{2}x\right):\dfrac{2}{7}=\dfrac{-21}{4}\)
3.\(\left|2x-\dfrac{3}{4}\right|=1\)
làm hộ mik 3 con này cái
2. tìm x
a. dfrac{6}{5}- x dfrac{-3}{4}
b. dfrac{3}{4}x - dfrac{2}{3}x dfrac{-7}{12}
c. | dfrac{2}{3}x - dfrac{1}{2}| -1 dfrac{5}{6}
d. 3,2 x - (dfrac{4}{5}+dfrac{2}{3}) : 3dfrac{2}{3}dfrac{7}{20}
Đọc tiếp
2. tìm x
a. \(\dfrac{6}{5}\)- x =\(\dfrac{-3}{4}\)
b. \(\dfrac{3}{4}\)x - \(\dfrac{2}{3}\)x = \(\dfrac{-7}{12}\)
c. | \(\dfrac{2}{3}\)x - \(\dfrac{1}{2}\)| -1 = \(\dfrac{5}{6}\)
d. 3,2 x - (\(\dfrac{4}{5}\)+\(\dfrac{2}{3}\)) : \(3\dfrac{2}{3}\)=\(\dfrac{7}{20}\)
text{Tìm x, biết:}a) x-dfrac{2}{3.5}-dfrac{2}{5.7}-dfrac{2}{7.9}-dfrac{2}{9.11}-dfrac{2}{11.13}-dfrac{2}{13.15}dfrac{2}{5}b) dfrac{1}{2.3}.x+dfrac{1}{3.4}.x+dfrac{1}{4.5}.x+...+dfrac{1}{49.50}.x1c) x-dfrac{20}{11.3}-dfrac{20}{13.15}-...-dfrac{53}{55}dfrac{3}{11}d) x+dfrac{4}{5.9}+dfrac{4}{9.13}+...+dfrac{4}{41.45}dfrac{-37}{45}e) left(dfrac{11}{12}.dfrac{11}{2.23}.dfrac{11}{23.34}...dfrac{11}{89.100}right).xdfrac{5}{3}f) left(dfrac{2}{11.13}.dfrac{2}{13.15}.dfrac{2}{15.17}...dfrac{2}{19.21}right...
Đọc tiếp
\(\text{Tìm x, biết:}\)
\(a\)) \(x-\dfrac{2}{3.5}-\dfrac{2}{5.7}-\dfrac{2}{7.9}-\dfrac{2}{9.11}-\dfrac{2}{11.13}-\dfrac{2}{13.15}=\dfrac{2}{5}\)
\(b\)) \(\dfrac{1}{2.3}.x+\dfrac{1}{3.4}.x+\dfrac{1}{4.5}.x+...+\dfrac{1}{49.50}.x=1\)
\(c\)) \(x-\dfrac{20}{11.3}-\dfrac{20}{13.15}-...-\dfrac{53}{55}=\dfrac{3}{11}\)
\(d\)) \(x+\dfrac{4}{5.9}+\dfrac{4}{9.13}+...+\dfrac{4}{41.45}=\dfrac{-37}{45}\)
\(e\)) \(\left(\dfrac{11}{12}.\dfrac{11}{2.23}.\dfrac{11}{23.34}...\dfrac{11}{89.100}\right).x=\dfrac{5}{3}\)
\(f\)) \(\left(\dfrac{2}{11.13}.\dfrac{2}{13.15}.\dfrac{2}{15.17}...\dfrac{2}{19.21}\right)-x+4+\dfrac{221}{231}=\dfrac{7}{3}\)
tìm x,y thuộc z
a. \(\dfrac{-1}{4}:\dfrac{-3}{4}+\dfrac{1}{2}< x< \dfrac{7}{8}-\dfrac{1}{2}:\dfrac{-5}{6}\)
\(x-\dfrac{1}{5}=\dfrac{3}{4}\)
\(\dfrac{2}{5}x+\dfrac{1}{4}=\dfrac{1}{8}\)