\(n_{Al}=\dfrac{10,8}{27}=0,4\left(mol\right)\\ PTHH:4Al+3O_2\rightarrow^{t^o}2Al_2O_3\\ \Rightarrow\left\{{}\begin{matrix}n_{O_2}=\dfrac{3}{4}n_{Al}=0,3\left(mol\right)\\n_{Al_2O_3}=\dfrac{1}{2}n_{Al}=0,2\left(mol\right)\end{matrix}\right.\\ \Rightarrow\left\{{}\begin{matrix}V=V_{O_2}=0,3\cdot22,4=6,72\left(l\right)\\a=m_{Al_2O_3}=0,2\cdot102=20,4\left(g\right)\end{matrix}\right.\)
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