a) CO2+2KOH-->K2CO3+H2O
b) Ta có
n CO2=2,464/22,4=0,11(mol)
n KOH=0,4.0,85=0,34(mol)
----->KOH dư..xảy ra 1 TH
Theo pthh
n KOH=2n CO2=0,22(mol)
n KOH dư=0,34-0,22=0,12(mol)
CM KOH=0,12/0,4=0,3(M)
Theo pthh
n K2CO3=n CO2=0,11(mol)
CM K2CO3=0,11/0,4=0,275(M)