CMR: 2(30 + 31 + 32 + 33 +....+ 3n-1) = 3n - 1
đặt A = 30 + 31 + 32 + 33 +....+ 3n-1
⇒ 3A = 31 + 32 + 33+ 34 +...+ 3n-1 + 3n
⇒ 3A - A = 31 + 32 + 33 + 34 +...+ 3n-1 + 3n
- (30 + 31 + 32 + 33 +....+ 3n-1)
⇒ 2A = 3n - 30
⇒ A = \(\frac{3^n-1}{2}\)
⇒ 2(30 + 31 + 32 + 33 +....+ 3n-1) = 2 . \(\frac{3^n-1}{2}\) = 3n - 1
vậy 2(30 + 31 + 32 + 33 +....+ 3n-1) = 3n - 1
Bài 31 : Tính :
a) \(\left(2^{-1}+3^{-1}\right):\left(2^{-1}-3^{-1}\right)+\left(2^{-1}.2^0\right):2^3\)
b) \(\left(-\frac{1}{3}\right)^{-1}-\left(-\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2\)
c) \(\text{[}\left(0,1\right)^2\text{]}^0+\text{[}\left(\frac{1}{7}\right)^1\text{]}^2.\frac{1}{49}.\text{[}\left(2^3\right)^3:2^5\text{]}\)
Mong các cao nhân giúp ak , đang cần gấp
Bài 1: Tìm x biết: \(\left|x-3\right|+\left|x+2\right|=7\)
Bài 2: CMR: \(\frac{1}{4}+\frac{1}{4^2}+\frac{1}{4^3}+...+\frac{1}{4^{999}}+\frac{1}{4^{1000}}< \frac{1}{3}\)
Bài 3: Tìm x biết:
a) \(x\left(x-2\right)\left(x-3\right)>0\)
b) \(x\left(x-2\right)\left(x-3\right)< 0\)
thực hiên phép tính :
a, \(\left(3^2\right)^2-\left(2^3\right)^2-\left(-5^2\right)^2\)
b, \(2^3+3.\left(-\dfrac{1}{2}\right)^0-\left(\dfrac{1}{2}\right)^2.4+\left(\left(-2\right)^2:\dfrac{1}{2}\right):8\)
c, \(\left(4.2^5\right):\left(2^3.\dfrac{1}{16}\right)\)
d, \(A=\dfrac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\dfrac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
1, thực hiện phép tính
\(\dfrac{\left(\dfrac{2}{5}\right)^9.10^9-\left(\dfrac{-9}{4}\right)^5:\left(\dfrac{-3}{16}\right)^{10}}{4^{12}+16^9}\)
2,CMR:\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+.......+\dfrac{1}{n^2}< \dfrac{2}{3}\)với n\(\ge\)4
tìm số tự nhiên thỏa mãn điều kiện
\(2\cdot2^2+3\cdot2^3+4\cdot2^4+........+n\cdot2^n=2^{n+11}\)
rút gọn : \(A=\left(\dfrac{2}{5}-\dfrac{5}{2}+\dfrac{1}{10}\right):\left(\dfrac{5}{2}-\dfrac{2}{3}+\dfrac{1}{12}\right)\)
tính:\(B=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+......+\dfrac{1}{2017}}{\dfrac{2016}{1}+\dfrac{2003}{2}+\dfrac{2002}{3}+.......+\dfrac{1}{2016}}\)
CMR :\(5a+2b⋮13\Leftrightarrow9a+b⋮13\left(a,b\in Z\right)\)
3/a)\(M\left(x\right)=\frac{1}{2}x^2-3x-x^3+3\)
\(=-x^3+\frac{1}{2}x^2-3x+3\)
\(N\left(x\right)=-4x+x^2+\frac{1}{2}x^3+6\)
\(=\frac{1}{2}x^3+x^2-4x^3+6\)
b)Ta có:\(\text{A}\left(x\right)=M\left(x\right)-N\left(x\right)\)
hay \(\text{A}\left(x\right)=\left(-x^3+\frac{1}{2}x^2-3x+3\right)-\left(\frac{1}{2}x^3+x^2-4x+6\right)\)
\(=-x^3+\frac{1}{2}x^2-3x+3-\frac{1}{2}x^3-x^2+4x-6\)
\(=-\frac{3}{2}x^3-\frac{1}{2}x^2+x-3\)
Đặt\(\text{A}\left(x\right)=0\)
\(\Rightarrow-\frac{3}{2}x^3-\frac{1}{2}x^2+x-3=0\)
\(-\frac{3}{2}x^3-\frac{1}{2}x^2=-x+3\)
\(-2\left(x^3-x^2\right)=-x+3\)
\(x^3-x^2+x=3+2=5\)
\(x^2=5\)
\(\Rightarrow x=\sqrt{5}\)
Vậy \(\text{A}\left(x\right)\) có 1 nghiệm là \(\sqrt{5}\)
Tìm x biết: \(x-0.\left(3\right)=3\frac{1}{3}+0.4\left(2\right)\) (Chú ý: \(0.\left(3\right)\) và \(0.4\left(2\right)\) là số thập phân vô hạn tuần hoàn các bn nha)
Cho B = \(1+\dfrac{1}{2}\left(1+2\right)+\dfrac{1}{3}\left(1+2+3\right)+\dfrac{1}{4}\left(1+2+3+4\right)+...+\dfrac{1}{x}\left(1+2+3+...+x\right)\)
Tìm số nguyên dương để B = 115
Cho \(B=1+\dfrac{1}{2}\left(1+2\right)+\dfrac{1}{3}\left(1+2+3\right)+\dfrac{1}{4}\left(1+2+3+4\right)+...+\dfrac{1}{x}\left(1+2+3+...+x\right)\)
Tìm số nguyên dương x biết B = 115
