Ta có:
1ab1 = 1000 + 100.a + 10.b + 1
1ba1 = 1000 + 100.b + 10.a + 1
\(\Rightarrow\) 1ab1 - 1ba1 = ( 1000 + 100.a + 10.b + 1 ) - ( 1000 + 100.b + 10.a + 1)
= 1000 + 100.a + 10.b + 1 - 1000 - 100.b - 10.a - 1
= ( 1000 + 1 ) + 100.a + 10.b + (- 1000 - 1 ) -100.b - 10.a
= 1001 + 100.a + 10.b - 1001 - 100.b - 10.a
= 100.a + 10.b - 100.b - 10.a
= a(100 - 10 ) - b(100-10)
= a.90 - b.90
= 90.(a-b) chia hết cho 90
Vậy 1ab1 - 1ba1 chia hết cho 90
Ta có:
1ab1= 1000 + a.100 + b.10 + 1
1ba1= 1000 + b.100 + a.10 + 1
1ab1 - 1ba1=(1000 + 100a + 10b + 1) - (1000 + 100b + 10a + 1)
=1000 + 100a + 10b + 1 - 1000 - 100b - 10a - 1
=(1000 - 1000) + (100a - 10a) + (100b - 10b) + (1 - 1)
=90a - 90b=90.(a - b) ⋮ 90
Vậy 1ab1 - 1ba1 ⋮ 90
Ta có :
\(\overline{1ab1}=1000+100a+10b+1\)
\(\overline{1ba1}=1000+100b+10a+1\)
\(\Rightarrow\overline{1ab1}-\overline{1ba1}=\)(1000 + 100a +10b + 1) - (1000 + 100b + 10a + 1)
= (1000 - 1000) + (100a - 10a) + (10b - 100b)+(1 - 1)
= 90a - 90b = 90(a + b) ⋮ 90
bn ơi nếu thấy đúng cho xin 1 tick nha
