\(A=\dfrac{1}{2^2}+\dfrac{1}{3^2}+...+\dfrac{1}{10^2}\)
\(A< \dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{9.10}=B\)
\(B=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\)
\(B=1-\dfrac{1}{10}< 1\)
\(A< B< 1\Rightarrow A< 1\) => dpcm