\(S=1\cdot2+2\cdot3+...+n\left(n+1\right)\)
\(3S=1\cdot2\cdot3+2\cdot3\cdot\left(4-1\right)+...+n\left(n+1\right)\left[\left(n+2\right)-\left(n-1\right)\right]\)
\(3S=1\cdot2\cdot3+2\cdot3\cdot4-1\cdot2\cdot3+...+n\left(n+1\right)\left(n+2\right)-\left(n-1\right)n\left(n+1\right)\)
\(3S=n\left(n+1\right)\left(n+2\right)\Rightarrow S=\frac{n\left(n+1\right)\left(n+2\right)}{3}\)