Câu a :
\(\dfrac{10^{2002}+2}{3}\) \(\in N\) \(\Rightarrow10^{2002}+2⋮3\)
Ta thấy :
\(10^{2002}=100.........00+2=100.........02\) \(⋮3\)
Câu b :
\(\dfrac{10^{2003}+8}{9}\in N\Rightarrow10^{2003}+8⋮9\)
Ta thấy :
\(10^{2003}=100.......00+8=100........08\)\(⋮9\)