Áp dụng BĐT AM-GM ta có:
\(P=x+y+\dfrac{6}{x}+\dfrac{24}{y}\)
\(=x+\dfrac{4}{x}+y+\dfrac{16}{y}+\dfrac{2}{x}+\dfrac{8}{y}\)
\(\ge2\sqrt{x\cdot\dfrac{4}{x}}+2\sqrt{y\cdot\dfrac{16}{y}}+2\left(\dfrac{1}{x}+\dfrac{4}{y}\right)\)
\(\ge4+8+2\dfrac{\left(1+2\right)^2}{x+y}\ge15\)
Xảy ra khi \(x=2;y=4\)