\(P=\dfrac{xy}{z}+\dfrac{yz}{x}+\dfrac{zx}{y}=\dfrac{1}{2}\left[\left(\dfrac{xy}{z}+\dfrac{yz}{x}\right)+\left(\dfrac{xy}{z}+\dfrac{zx}{y}\right)+\left(\dfrac{yz}{x}+\dfrac{zx}{y}\right)\right]\)
\(\ge\dfrac{1}{2}\left(2y+2x+2z\right)=x+y+z=2014\)
Dấu = xảy ra khi \(x=y=z=\dfrac{2014}{3}\)