Ta có: \(\widehat{B}-\widehat{C}=50^0\)
\(\widehat{ADB}+\widehat{B}=\widehat{ADC}+\widehat{C}\)
\(\Leftrightarrow\widehat{ADB}-\widehat{ADC}=\widehat{C}-\widehat{B}=-50^0\)
mà \(\widehat{ADB}+\widehat{ADC}=180^0\)
nên \(\widehat{ADB}=65^0;\widehat{ADC}=115^0\)