Ta có: \(\widehat{B}+\widehat{D}=90^o;\widehat{B}=\widehat{C_2}\)
\(\Rightarrow\widehat{C_2}+\widehat{D}=90^o\left(1\right)\)
Mà \(\widehat{C_2}+\widehat{C_1}=180^o\)
\(\Rightarrow\widehat{C_1}+\widehat{C_2}-\left(\widehat{C_2}+\widehat{D}\right)=180^o-90^o=90^o\\ \Rightarrow\widehat{C_1}-\widehat{D}=90^o\)
Hay: \(\widehat{DCA}-\widehat{ADC}=90^o\)
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