a: \(\widehat{ABD}+\widehat{A}=90^0\)
\(\widehat{ACE}+\widehat{A}=90^0\)
Do đó: \(\widehat{ABD}=\widehat{ACE}\)
=>\(180^0-\widehat{ABD}=180^0-\widehat{ACE}\)
hay \(\widehat{ABH}=\widehat{ACK}\)
b: Xét ΔABH và ΔKCA có
AB=KC
\(\widehat{ABH}=\widehat{ACK}\)
BH=CA
Do đó: ΔABH=ΔKCA
Suy ra: AH=AK