Giải:
Ta có:
\(S=3+3^3+3^5+...+3^{2015}\)
\(\Leftrightarrow3^2S=3^2\left(3+3^3+3^5+...+3^{2015}\right)\)
\(\Leftrightarrow9S=3^3+3^5+3^7+...+3^{2017}\)
Lấy \(9S-S\), ta được:
\(9S-S=3^{2017}-3\)
\(\Leftrightarrow8S=3^{2017}-3\)
\(\Leftrightarrow S=\dfrac{3^{2017}-3}{8}\)
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