\(B=\frac{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+98\right)}{1.98+2.97+3.96+...+98.1}\)
<=>\(B=\frac{1+1+2+1+2+3+...+1+2+3+...+98}{1.98+2.97+3.96+...+98.1}\)
<=>\(B=\frac{\left(1+1+...+1\right)+\left(2+2+...+2\right)+\left(3+3+...+3\right)+...+98}{1.98+2.97+3.96+...+98.1}\)
<=>\(B=\frac{1.98+2.97+3.96+...+98.1}{1.98+2.97+3.96+...+98.1}\)
<=> B = 1