PTHH: 2Na+2HCl--->2NaCl+H2
2Na+2H2O--->2NaOH+H2(2)
2NaOH+2Al+H2O--->2NaAlO2+2H2(3)
Ta có
n AL=0,27/27=0,01(mol)
Theo pthh3
n NaOH=n Al=0,01(mol)
n HCl=0,5.0,2=0,1(mol
Theo pthh1
n Na=n HCl=0,1(mol)
Theo pthh2
n Na=n NaOH(dư ở pt3)=0,01(mol)
\(\sum n_{Na}=0,11\left(mol\right)\)
m=m Na=0,11.23=2,53(g)
Theo pthh1
n H2=1/2n HCl=0,05(mol)
Theo pthh2
n H2=1/2n\(_{NaOH}=0,005\left(mol\right)\)
\(\sum n_{H2}=0,055\left(mol\right)\)
V=V H2=0,055.22,4=1,232(l)
Chúc bạn học tốt :))