Theo đề ta có;
\(\dfrac{2}{2.3}=2.\left(\dfrac{1}{2}-\dfrac{1}{3}\right)\)
=> \(\dfrac{2}{6}=2.\left(\dfrac{3}{6}-\dfrac{2}{6}\right)\)
=> \(\dfrac{2}{6}=\dfrac{2.1}{6}\)
=> \(\dfrac{2}{6}=\dfrac{2}{6}\) ( đúng)
Nhưng nếu:
\(\dfrac{2}{2.3}=2.\left(\dfrac{1}{2}+\dfrac{1}{3}\right)\)
=> \(\dfrac{2}{2.3}=2.\left(\dfrac{3}{6}+\dfrac{2}{6}\right)\)
=> \(\dfrac{2}{6}=\dfrac{2.5}{6}\)
=> \(\dfrac{2}{6}=\dfrac{10}{6}\)( Vô lí)
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