\(MC=\frac{3}{4}AC\Rightarrow\)\(\overrightarrow{MC}=\frac{3}{4}\overrightarrow{AC}\)
\(\overrightarrow{AC}=\overrightarrow{AB}+\overrightarrow{BC}=\overrightarrow{AB}+\overrightarrow{AD}\) \(\Rightarrow\overrightarrow{MC}=\frac{3}{4}\overrightarrow{AB}+\frac{3}{4}\overrightarrow{AD}\)
\(\overrightarrow{CN}=\frac{1}{2}\overrightarrow{CD}=-\frac{1}{2}\overrightarrow{AB}\)
\(\overrightarrow{MN}=\overrightarrow{MC}+\overrightarrow{CN}=\frac{3}{4}\overrightarrow{AB}+\frac{3}{4}\overrightarrow{AD}-\frac{1}{2}\overrightarrow{AB}=\frac{1}{4}\overrightarrow{AB}+\frac{3}{4}\overrightarrow{AD}\)
\(\Rightarrow a+b=1\)