\(f\left(x\right)=x^2-1\)
Để \(f\left(x\right)=3\)
\(\Rightarrow x^2-1=3\)
\(\Rightarrow x^2=3+1\)
\(\Rightarrow x^2=4\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{2;-2\right\}\) thì \(f\left(x\right)=3.\)
Chúc bạn học tốt!
f(3)= \(^{3^2-1}\)= 9-1=8