Ta có: f(x) = 2x3 - 3x + x2 - 5x - 2x2 + 1
g(x) = 3x2 - 2x -x3 + 2
=> f(x) + g(x) = ( 2x3 - 3x + x2 - 5x - 2x2 + 1 ) + ( 3x2 - 2x - x3 + 2 )
= 2x3 - 3x + x2 - 5x - 2x2 + 1 + 3x2 - 2x - x3 + 2
= ( 2x3 - x3 ) + ( x2 - 2x2 + 3x2 ) - ( 3x + 5x + 2x ) + ( 1 + 2 )
= x3 + 2x2 - 10x +3
=> f(x) - g(x) = ( 2x3 - 3x + x2 - 5x - 2x2 + 1 ) - ( 3x2 - 2x - x3 + 2 )
= 2x3 - 3x + x2 - 5x - 2x2 + 1 - 3x2 + 2x + x3 - 2
= ( 2x3 + x3 ) - ( 2x2 - x2 + 3x2 ) - ( 3x + 5x - 2x) - ( 2 - 1 )
= 3x3 - 4x2 - 6x - 1
Chuk bn hk tốt!