\(F=\dfrac{1}{1.2.3.4}+\dfrac{1}{2.3.4.5}+...+\dfrac{1}{47.48.49.50}\\ =\dfrac{1}{3}\left(\dfrac{1}{1.2.3}-\dfrac{1}{2.3.4}+\dfrac{1}{2.3.4}-\dfrac{1}{3.4.5}+...+\dfrac{1}{47.48.49}-\dfrac{1}{48.49.50}\right)\\ =\dfrac{1}{3}\left(\dfrac{1}{6}-\dfrac{1}{117600}\right)\\ =\dfrac{1}{3}.\dfrac{6533}{39200}\\ =\)