Xét \(\Delta ABC\) có \(\widehat{A}=90^0\)
\(\Leftrightarrow BC^2=AB^2+AC^2\) (định lí Py ta go)
\(\Leftrightarrow BC^2=1^2+\sqrt{3}^2\)
\(\Leftrightarrow BC^2=4cm\)
\(\Leftrightarrow BC=2cm\)
Xét \(\Delta ABC\) có : \(\widehat{A}=90^0;\) \(AC=\dfrac{1}{2}BC\)
\(\Leftrightarrow\widehat{B}=30^0\)
\(\Leftrightarrow BC=\sqrt{10}cm\)