Gọi : nH2O =x ; nC2H5OH = y
PTHH :
2Na + 2H2O - > 2NaOH + H2
xmol....xmol........................1/2xmol
2Na + 2C2H5OH - > 2C2H5ONa + H2
ymol....ymol ......................................1/2ymol
Ta có HPT : \(\left\{{}\begin{matrix}18x+46y=14,6\\0,5\left(x+y\right)=0,25\end{matrix}\right.=>x=0,3;y=0,2\)
=> m(etylic) trong dd = 0,2.46 = 9,2(g)