a)\(\text{Xét }\Delta ABC:\widehat{BAC}+\widehat{ABC}+\widehat{ACB}=180^o\left(\text{định lý tổng 3 góc của tam giác}\right)\)
\(\text{Mà }\widehat{BAC}=60^o,\widehat{ABC}=45^o\)
\(\Rightarrow60^o+45^o+\widehat{ACB}=180^o\)
\(\Rightarrow\widehat{ACB}=180^o-45^o-60^o\)
\(\Rightarrow\widehat{ACB}=75^o\)