a: \(=\dfrac{x+x-5-2x-10}{\left(x-5\right)\left(x+5\right)}\cdot\dfrac{x+5}{1-x}=\dfrac{-15}{\left(1-x\right)\left(x-5\right)}=\dfrac{15}{\left(x-1\right)\left(x-5\right)}\)
b: Khi x=-4 thì
\(A=\dfrac{15}{\left(-4-1\right)\left(-4-5\right)}=\dfrac{15}{\left(-5\right)\cdot\left(-9\right)}=\dfrac{15}{45}=\dfrac{1}{3}\)