a: ĐKXĐ: x>=0; x<>1
\(A=\dfrac{x+\sqrt{x}-2\sqrt{x}+2-2}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\)
\(=\dfrac{x-\sqrt{x}}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}=\dfrac{\sqrt{x}}{\sqrt{x}+1}\)
b: Thay x=9 vào A, ta được:
\(A=\dfrac{3}{3+1}=\dfrac{3}{4}\)