a) \(\widehat{AOM}=\widehat{BON}=90^o\) (giả thiết)
b) Ta có:
\(\widehat{NOA}=\widehat{AOB}-\widehat{BON}\)
\(\Leftrightarrow\widehat{NOA}=120^o-90^o\)
\(\Leftrightarrow\widehat{NOA}=30^o\)
Ta có:\(\widehat{MOB}=\widehat{AOB}-\widehat{AOM}\)
\(\Leftrightarrow\widehat{MOB}=120^o-90^o\)
\(\Leftrightarrow\widehat{MOB}=30^O\)
Vậy \(\Leftrightarrow\widehat{NOA}=\widehat{MOB}=30^o\)
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