\(\frac{9}{11}\)=\(\frac{1}{\frac{11}{9}}\)=\(\frac{1}{1+\frac{2}{9}}\)=\(\frac{1}{1+\frac{1}{\frac{9}{2}}}\)=\(\frac{1}{1+\frac{1}{4+\frac{1}{2}}}\)
=> a=1 ; b=4 ; c=2
Ta có:\(\frac{9}{11}\)=\(\frac{1}{\frac{11}{9}}\)=\(\frac{1}{1+\frac{1}{\frac{9}{2}}}\)=\(\frac{1}{1+\frac{1}{4+\frac{1}{2}}}\)\(\Rightarrow\)a=1;b=4;c=2.Nhớ tick cho mik nhé