\(\frac{a}{x+1}+\frac{b}{x-2}=\frac{32x-19}{x^2-x-2}\)
\(\Leftrightarrow\frac{a\left(x-2\right)+b\left(x+1\right)}{\left(x-2\right)\left(x+1\right)}=\frac{32x-19}{\left(x-2\right)\left(x+1\right)}\)
\(\Leftrightarrow\frac{x\left(a+b\right)-\left(2a-b\right)}{\left(x-2\right)\left(x+1\right)}=\frac{32x-19}{\left(x-2\right)\left(x+1\right)}\)
Suy ra: a+b=32 và 2a-b=19
đến đây bạn tự giải nhé