Ta có : \(A=\frac{-5\sqrt{x}+2}{\sqrt{x}+3}=\frac{-5\sqrt{x}-15+17}{\sqrt{x}+3}=\frac{-5\left(\sqrt{x}+3\right)+17}{\sqrt{x}+3}=-5+\frac{17}{\sqrt{x}+3}\)
Ta thấy : \(\sqrt{x}\ge0\)
=> \(-5+\frac{17}{\sqrt{x}+3}\le-5+\frac{17}{3}\)
=> MaxA = \(\frac{2}{3}\) khi \(\sqrt{x}=0\) <=> x = 0