Đặt a/b=c/d=k
=>a=bk; c=dk
\(\left(\dfrac{a-c}{b-d}\right)^{2023}=\left(\dfrac{bk-dk}{b-d}\right)^{2023}=k^{2023}\)
\(\dfrac{a^{2023}+c^{2023}}{b^{2023}+d^{2023}}=\dfrac{b^{2023}k^{2023}+d^{2023}k^{2023}}{b^{2023}+d^{2023}}=k^{2023}\)
=>\(\left(\dfrac{a-c}{b-d}\right)^{2023}=\dfrac{a^{2023}+c^{2023}}{b^{2023}+d^{2023}}\)