Violympic toán 9
Các câu hỏi tương tự
cho a,b,c >0
cmr: \(\sum\dfrac{a\left(b+c\right)}{bc+a^2}\le\sum\dfrac{1}{a}\)
Cho a, b, c > 0 thoã mãn: ab + bc + ca = 3. CMR: \(\dfrac{1}{1+a^2\left(b+c\right)}+\dfrac{1}{1+b^2\left(c+a\right)}+\dfrac{1}{1+c^2\left(a+b\right)}\le\dfrac{3}{abc}\)
Cho a,b,c>0 thỏa mãn a+b+c=3 CMR:
\(\dfrac{a^4}{\left(a+2\right)\left(b+2\right)}+\dfrac{b^4}{\left(b+2\right)\left(c+2\right)}+\dfrac{c^4}{\left(c+2\right)\left(a+2\right)}\ge\dfrac{1}{3}\)
19 tháng 10 2019 lúc 17:49
1. cho 0 ale ble c . Cmr: frac{2a^2}{b^2+c^2}+frac{2b^2}{c^2+a^2}+frac{2c^2}{a^2+b^2}lefrac{a^2}{b}+frac{b^2}{c}+frac{c^2}{a}
2. cho a,b,cge0. cmr: a^2+b^2+c^2+3sqrt[3]{left(abcright)^2}ge2left(ab+bc+caright)
3. a,b,c0. Cmr: sqrt{left(a^2b+b^2c+c^2aright)left(ab^2+bc^2+ca^2right)}ge abc+sqrt[3]{left(a^3+abcright)left(b^3+abcright)left(c^3+abcright)}
4. a,b,c0. Tìm Min Pleft(frac{a}{a+b}right)^4+left(frac{b}{b+c}right)^4+left(frac{c}{c+a}right)^4
Đọc tiếp
1. cho \(0< a\le b\le c\) . Cmr: \(\frac{2a^2}{b^2+c^2}+\frac{2b^2}{c^2+a^2}+\frac{2c^2}{a^2+b^2}\le\frac{a^2}{b}+\frac{b^2}{c}+\frac{c^2}{a}\)
2. cho \(a,b,c\ge0\). cmr: \(a^2+b^2+c^2+3\sqrt[3]{\left(abc\right)^2}\ge2\left(ab+bc+ca\right)\)
3. \(a,b,c>0.\) Cmr: \(\sqrt{\left(a^2b+b^2c+c^2a\right)\left(ab^2+bc^2+ca^2\right)}\ge abc+\sqrt[3]{\left(a^3+abc\right)\left(b^3+abc\right)\left(c^3+abc\right)}\)
4. \(a,b,c>0\). Tìm Min \(P=\left(\frac{a}{a+b}\right)^4+\left(\frac{b}{b+c}\right)^4+\left(\frac{c}{c+a}\right)^4\)
Cho a, b, c >0. CMR: \(\dfrac{a+b+c}{3}\) - \(\sqrt[3]{abc}\) ≤ \(\dfrac{\left(\sqrt{a}-\sqrt{b}\right)^2+\left(\sqrt{b}-\sqrt{c}\right)^2+\left(\sqrt{c}-\sqrt{a}\right)^2}{3}\)
Cho a,b,c là các số thực dương CMR : \(\dfrac{a}{\left(b+c\right)^2}+\dfrac{b}{\left(c+a\right)^2}+\dfrac{c}{\left(a+b\right)^2}\ge\dfrac{9}{4\left(a+b+c\right)}\)
Với mọi a,b,c . CMR
\(-\dfrac{1}{2}\le\dfrac{\left(a+b\right)\left(1-ab\right)}{\left(a^2+1\right)\left(b^2+1\right)}\le\dfrac{1}{2}\)
Cho \(0\le a\le b\le c\le1\). Tìm max
\(A=\left(a+b+c+3\right)\left(\dfrac{1}{a+1}+\dfrac{1}{b+1}+\dfrac{1}{c+1}\right)\)
23 tháng 6 2021 lúc 16:09
Cho a, b, c>0; abc=1. Cmr:
\(\dfrac{a^3}{b\left(c+2\right)}+\dfrac{b^3}{c\left(a+2\right)}+\dfrac{c^3}{a\left(b+2\right)}\ge1\)
Sao em làm chỉ ra >=3 thôi ạ)):